Asked by Dorcas
If the 2nd and 5 term of the GP is 6 and 48 respectful find the 10 term.
Answers
Answered by
mathhelper
ar = 6
ar^4 = 48
divide them:
ar^4 / ar = 48/6
r^3 = 8
r = 2
then from ar = 6, a = 3
then term(10) = ar^9 = 3(2^9) = 1536
ar^4 = 48
divide them:
ar^4 / ar = 48/6
r^3 = 8
r = 2
then from ar = 6, a = 3
then term(10) = ar^9 = 3(2^9) = 1536
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