Asked by Subash
A number of two-digits exceed four times the sum of its digit by 3.If 36 is added to the number,the digits are reversed.find the number
Answers
Answered by
mathhelper
let the tens digit of the number be x
let the unit digit of the number be y
so the number is 10x+y
10x+y = 4(x+y) + 3
6x - 3y = 3
2x - y = 1
10x+y + 36 = 10y + x
9x - 9y = -36
x - y = -4
subtract them:
x = 5
then 5 - y = -4
y = 9
the number is 59
check:
4 times the sum of its digits = 4(5+9) = 56, which exceed the number by 3
36 added to 59 = 95, which is the number reversed.
the number is 59
let the unit digit of the number be y
so the number is 10x+y
10x+y = 4(x+y) + 3
6x - 3y = 3
2x - y = 1
10x+y + 36 = 10y + x
9x - 9y = -36
x - y = -4
subtract them:
x = 5
then 5 - y = -4
y = 9
the number is 59
check:
4 times the sum of its digits = 4(5+9) = 56, which exceed the number by 3
36 added to 59 = 95, which is the number reversed.
the number is 59