a 3digit, and 1digit number have a sum of 147, a different of 133 and a product of 980. find the numbers, and then give their quatient

Answer 1

From the information above:

x - y = 133
x + y = 147

Find the value for x in one formula.

x = y + 133

Substitute that for x in the second formula and solve for y.

(y + 133) + y = 147

2y = 147 - 133 = 14

y = 7

Put the y value into the first formula and solve for x.

x = y + 133 = 7 + 133 = 140

Check by finding their product.

I hope this helps. Thanks for asking.