Asked by Gera
A rectangular metal block with side 1.5𝑚 by 1.2𝑚 by 1.0𝑚 rests on a horizontal surface .If the density of
the metal is 7000𝑘𝑔/𝑚3, calculates; i. Volume of the metal block, ii. Mass of metal block, iii. The
difference between maximum and the minimum pressure that the block can exerts on the surface
the metal is 7000𝑘𝑔/𝑚3, calculates; i. Volume of the metal block, ii. Mass of metal block, iii. The
difference between maximum and the minimum pressure that the block can exerts on the surface
Answers
Answered by
oobleck
volume = 1.5m*1.2m*1.0m = 1.8 m^3
mass = volume * density
since pressure = force/area,
maximum pressure is when the smallest face is resting on the surface
minimum pressure is when the largest face is resting on the surface.
I assume you know how to find the area of a rectangular face.
mass = volume * density
since pressure = force/area,
maximum pressure is when the smallest face is resting on the surface
minimum pressure is when the largest face is resting on the surface.
I assume you know how to find the area of a rectangular face.
Answered by
Anonymous
remember weight = mass * g
and as you know pressure = weight in Newtons / area in square meters
and as you know pressure = weight in Newtons / area in square meters
Answered by
Anonymous
in Pascals :)
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