Asked by Atharv Mundhe
Gas A diffuses 2 times faster than gas B. Ratio of their molecular weights is:
Answers
Answered by
DrBob222
Assign some values just to make the problem easier to solve; i.e., let rate for gas B = 50 mL/hr, then rate for gas A = 100 mL/hr
(rate A/rate B) = sqrt (molar mass B/molar mass A)
(100/50) = sqrt (mm B/mm A)
2 = sqrt (mm B/mm A)
4 = molar mass B/molar mass A
(rate A/rate B) = sqrt (molar mass B/molar mass A)
(100/50) = sqrt (mm B/mm A)
2 = sqrt (mm B/mm A)
4 = molar mass B/molar mass A
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