Question
A gas diffuses 3.98 times slower than H2 at the same temperature and pressure. What is the molar mass of the gas?
Answers
DrBob222
mm = molar mass
rate gas = 1 L/min (I just made up that number)
Then rate H2 = 3.98*1 = 3.98L/min.
Substitute into the below equation and solve for mm gas.
(rate H2/rate gas)= sqrt (mmgas/mm H2)
rate gas = 1 L/min (I just made up that number)
Then rate H2 = 3.98*1 = 3.98L/min.
Substitute into the below equation and solve for mm gas.
(rate H2/rate gas)= sqrt (mmgas/mm H2)