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18cm^3 of 1.0M H2SO4 just reacted with 24cm^3 of 1.5M NaOH to form sodium sulfate & water. Calculate the amounts in moles of sulfuric acid & sodium hydroxide reacting & write an equation for the reaction.

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mols H2SO4 = M x L = 0.018
mols NaOH = M x L = 0.036

2NaOH + H2SO4 ==> Na2SO4 + 2H2O
0.036....0.018....0.018....0.036

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