Asked by Devin
A 0.885 M solution of sulfuric acid (H2SO4) is to be reacted with a 0.552 M solution of sodium hydroxide to make sodium sulfate and water. How many L of the H2SO4 solution will react with 0.842 L of the NaOH solution? Give your answer to 3 decimal places.
Answers
Answered by
DrBob222
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols H2SO4 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2SO4 to mols NaOH.
Then M NaOH = mols NaOH/L NaOH. You know mols and M, solve for L.
mols H2SO4 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2SO4 to mols NaOH.
Then M NaOH = mols NaOH/L NaOH. You know mols and M, solve for L.
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