Asked by Dp
A 5-quart solution of sulfuric acid and water is 60% acid. If a gallon of water is added, what percent of the resulting solution is acid?
a. 33 1/3%
b. 40%
c. 50%
D. none
a. 33 1/3%
b. 40%
c. 50%
D. none
Answers
Answered by
elysia
Saw this question earlier on another site:
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A 5-quart solution of sulfuric acid and water is 60% acid.
If a gallon of water is added, what percent of the resulting solution is acid?
Let x = per cent when a gallon of water is added
Change 1 gallon to 4 quarts
The amt of acid remains the same
60(5) = x(5 + 4)
300 = 9x
x = 300/9
x = 33 1/3 percent
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A 5-quart solution of sulfuric acid and water is 60% acid.
If a gallon of water is added, what percent of the resulting solution is acid?
Let x = per cent when a gallon of water is added
Change 1 gallon to 4 quarts
The amt of acid remains the same
60(5) = x(5 + 4)
300 = 9x
x = 300/9
x = 33 1/3 percent
Answered by
NANI
1 gal=4qt
5qt*0.6= 3 qt
there was 3 qt of acid in the original 5qt solution
5qt+1gal=5qt+4qt=9 quarts
3 quarts/9 quarts =1/3= 33 1/3%
5qt*0.6= 3 qt
there was 3 qt of acid in the original 5qt solution
5qt+1gal=5qt+4qt=9 quarts
3 quarts/9 quarts =1/3= 33 1/3%
Answered by
henry2,
0.6*5 = 3qts. acid and 2qts. water.
5+4 = 9qt. sol.
9-6 = 3qts acid.
3/9 * 100% = 33 1/3 % acid.
5+4 = 9qt. sol.
9-6 = 3qts acid.
3/9 * 100% = 33 1/3 % acid.
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