Asked by Razor

A spring streatches by 6cm when supporting a load of 15N what load would make the spring extend by 25mm
Answered by person
F = k x
15 = k * 6
k = 15/6
5 = (15/6) x
x = 5 * (6/15 ) = 2 cm
Answered by oobleck
x/25 = 15/6
x = 25/6 * 15 = ____ N
Answered by JAC OB254
F=ke, thus k=F/e
k=15/0.06
k=250N/m

when e=25mm=0.025mm
then, F=250×0.025
=6.25N
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