Question

If 2.0gram of calcium carbonate were reacted with excess dilute hydrochloric acid. What volume of carbon dioxide would be given out at S.T.P
Nothing
write the equation.
determine how many moles of CO2 you will get
each mole occupies 22.4 L at STP
CaCO3(s) + 2HCl(aq)> CaCl2(aq) +CO2(g)+H2O(l)
RFM of CaCO3 =(2×40)+12+(3×16)
=80+12+48=140
No of moles of CaCO3 that reacted =2/140
=1/70 moles
mole ratio of CaCO3 to CO2 is 1:1
therefore, the no of moles of CO2 produced= 1/70 moles

Molar gas volume at STP =22.4L
1 mole=22.4L
1/70 moles=??
=1/70×22.4
=0.32L

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