Asked by blah

Calcium carbonate can be decomposed by heating according to the equation Below. WHat is the percentage yield of calcium oxide in this reaction if 12.6g of CaO is obtained when 25.9g of CaCO3 is heated ?

CaCO3(S) -> CaO (s) + CO2 (g)
Answered by DrBob222
mols CaCO3 = 25.9/molar mass CaCO3.
mols CaO = same as mols CaCO3 according to the balanced equation.
g CaO = mols CaO x molar mass CaO. This is the theoretical yield(TY). The actual yield (AY) is 12.6g
%yield = (AY/TY)*100 = ?
Answered by jacob
12.6/25.9*100=48.6
There are no AI answers yet. The ability to request AI answers is coming soon!