Asked by Anonymous
If 20.0 g of NaCl is added to 100.0 mL of water, what is the %(m/m) of the NaCl in solution? Assume the density of water is 1.00 g/mL
Answers
Answered by
DrBob222
% w/w = % m/m = (mass solute/total mass of solution)*100 = ?
mass solute = 20.0 g NaCl
totalmass solution = 20.0 + 100.0 = 120.0
Substitute and solve
mass solute = 20.0 g NaCl
totalmass solution = 20.0 + 100.0 = 120.0
Substitute and solve
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