Asked by Anonymous
if 12.8g of NaCl is added to 243.2 mL of water (density (1.00g/mL)). the volume occupied by the solution is 250.0 mL. Calculate the density of the salt water.
Answers
Answered by
Ayanda
Volfor nacl(solute)=v of solution - v of water(solvent
=250.0 - 243.2
= 6.80mL
Density (salt )= mass/ volume
=12.8/6.80
=1.88 g/mL
=250.0 - 243.2
= 6.80mL
Density (salt )= mass/ volume
=12.8/6.80
=1.88 g/mL
Answered by
DrBob222
density salt water = mass salt water/volume salt water.
mass salt water = 243.2 + 12.8 = 256.0 g.
volume salt solution = 250.0
density = mass/volume = 256.0/250.0 = 1.02 g/mL
mass salt water = 243.2 + 12.8 = 256.0 g.
volume salt solution = 250.0
density = mass/volume = 256.0/250.0 = 1.02 g/mL
Answered by
Anonymous
22,342
Answered by
DrBob222
1.99 is not right.
22,342 is not right.
22,342 is not right.
Answered by
james
24.332
Answered by
DrBob222
I should have said 1.88 is not right.
24.332 is not right either. If you want to show your work I'll find the error for you. You would need over 6000 grams NaCl in 250 cc solution to have a density of over 24.
24.332 is not right either. If you want to show your work I'll find the error for you. You would need over 6000 grams NaCl in 250 cc solution to have a density of over 24.
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