Asked by Juma

In geometric progression sum of 2nd term and 3rd term is 12 and sum of 4th term and 5th term is 300 find first term and common ratio
MATHEMATICS

Answers

Answered by R_scott
a r + a r^2 = 12 ... a r (1 + r) = 12

a r^3 + a r^4 = 300 ... a r^3 (1 + r) = 300

dividing equations ... r^2 = 25 ... r = 5

substitute back to find a
Answered by mathhelper
ar +ar^2 = 12 ---> ar(1+r) = 12
ar^3 + ar^4 = 300 --> ar^3(1+r) = 300

divide the 2nd equation by the first:
r^2 = 300/12 = 25
r = ± 5
sub into ar(1+r) = 12
<b>if r = 5, 5a(6) = 12 ----> a = 2/5</b>
<b>if r = -5, -5a(-4) = 12 ----> a = 3/5</b>

check:
case 1: a = 2/5, r = 5, we have 2/5, 2, 10, 50, 250, ...
sum of 2nd and 3rd = 12, sum of 4th and 5th = 300, check!

case 2. a = 3/5, r = -5, we have 3/5, -3, 15, -75, 375
sum of 2nd and 3rd = -3+15 = 12, sum of 4th and 5th = -75+375 = 300,

my answers are correct
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