Question

A poll is given, showing 65% are in favor of a new building project.

If 6 people are chosen at random, what is the probability that exactly 4 of them favor the new building project?

Answer 1

prob(in favour) = 65/100 = 13/20
prob(not in favour) = 7/20

prob(4 of 6 are in favour) = C(6,4)(13/20)^4 (7/20)^2
= appr. .328