Asked by Mulsha
A 100 kg roller coaster is moving at 10 m/s while travelling 30 m above the ground. How fast will it be travelling when it reaches ground height?
Can you do an explanation with it too please whoever answers it
Can you do an explanation with it too please whoever answers it
Answers
Answered by
R_scott
total energy is ... 1/2 m v^2 + m g h ... (1/2 * 100 * 10^2) + (100 * 9.8 * 30)
... 5 kJ + 29.4 kJ = 34.4 kJ
potential energy becomes kinetic energy
at ground height ... 1/2 * 100 * v^2 = 34.4 kJ ... v^2 = 688 m^2/s^2
... 5 kJ + 29.4 kJ = 34.4 kJ
potential energy becomes kinetic energy
at ground height ... 1/2 * 100 * v^2 = 34.4 kJ ... v^2 = 688 m^2/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.