Asked by Isaac
Solve 8 = 36sin^2 3x+60sin3x+17, where x {0,2pi}
Answers
Answered by
oobleck
36sin^2 3x+60sin3x+17 = 8
36sin^2 3x + 60sin3x + 9 = 0
3(12sin^2 3x + 20sin3x + 3) = 0
3(6sin3x+1)(2sin3x+3) = 0
sin3x = -1/6
3x = -9.6° + 360k°
x = -3.2°+120k°
36sin^2 3x + 60sin3x + 9 = 0
3(12sin^2 3x + 20sin3x + 3) = 0
3(6sin3x+1)(2sin3x+3) = 0
sin3x = -1/6
3x = -9.6° + 360k°
x = -3.2°+120k°
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