Asked by Anonymous
A 400.0 g aluminum cooking pot is heated from 25.0°C to 99.0°C. What amount of heat energy does it absorb?
Answers
Answered by
DrBob222
J = mass x specific heat Al x (Tfinal-Tinitial)
J = 400 g x specific heat Al x (99 - 25) = ?
You will to look up the specific heat of Alumnum in J/g*celsius
J = 400 g x specific heat Al x (99 - 25) = ?
You will to look up the specific heat of Alumnum in J/g*celsius
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