Asked by Mbali
Eccentricity of 16x^2 +64y^2-1024=0
Answers
Answered by
mathhelper
16x^2 +64y^2-1024=0
16x^2 +64y^2 = 1024
divide by 1024
x^2/64 + y^2/16 = 1
you are looking at at ellipse with a = 8 and b = 4
In an ellipse in standard position like yours
c^2 = a^2 - b^2 = 64-16 = 48
c = √48 = 4√3
e = c/a = 4√3/8 = √3 / 2
16x^2 +64y^2 = 1024
divide by 1024
x^2/64 + y^2/16 = 1
you are looking at at ellipse with a = 8 and b = 4
In an ellipse in standard position like yours
c^2 = a^2 - b^2 = 64-16 = 48
c = √48 = 4√3
e = c/a = 4√3/8 = √3 / 2