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The logarithm of any number or alphabet to the base of itself equal
3 years ago

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Answered by mathhelper
log <sub>a</sub> a = 1

proof:
let log <sub>a</sub> a = x
then a^x = a
a^x = a^1
then x = 1
3 years ago
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The logarithm of any number or alphabet to the base of itself equal

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