Question
The logarithm of any number or alphabet to the base of itself equal
Answers
mathhelper
log <sub>a</sub> a = 1
proof:
let log <sub>a</sub> a = x
then a^x = a
a^x = a^1
then x = 1
proof:
let log <sub>a</sub> a = x
then a^x = a
a^x = a^1
then x = 1