Question

A student walked 4 km due east and then 15km in a direction of 37° north of east ,finally the walked due north for 3km ,how much is this displacement?

Answer 1

East:
E = 4 + 15 cos 37
North:
N = 3 + 15 sin 37
d = sqrt (E^2+N^2)
angle A clockwise from north
tan A = E / N

Answer 2

0972209372

Answer 3

18.4km

Answer 4

20km