Asked by Sharew

A Studet walked 4km due east and the 15km east of north in direaction of 37° north of east.finally he walked due north for 3km.how much is displacement.
Answered by oobleck
starting at (0,0) the student walked to
(x,y) = (4+15sin37° , 15cos37°+3)
the displacement is √(x^2+y^2)
in the direction NθE where tanθ = x/y
Answered by Ahmed
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Answered by Ahmed
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