Asked by Alexis
A population of bacteria is growing according to the equation
P(t) = 1650e^0.22t. Estimate when the population will about 5656.
P(t) = 1650e^0.22t. Estimate when the population will about 5656.
Answers
Answered by
oobleck
165 e^0.22t = 5656
e^0.22t = 34.278
0.22t = ln 34.278 = 3.535
t = 16.066
e^0.22t = 34.278
0.22t = ln 34.278 = 3.535
t = 16.066
Answered by
mathhelper
I think oobleck dropped a decimal place , it should be ....
1650 e^0.22t = 5656
e^0.22t = 3.4278
0.22t = ln 3.4278 = 1.23194...
t = 5.5997
If t is in years, it would take appr 5.6 years
1650 e^0.22t = 5656
e^0.22t = 3.4278
0.22t = ln 3.4278 = 1.23194...
t = 5.5997
If t is in years, it would take appr 5.6 years
Answered by
oobleck
nice save -- thx
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