Asked by Kevin
The ratio of 6th to the 2nd term of geometric sequence is 256. If the 3rd term of this sequence is32 determine first and fifth term
Answers
Answered by
mathhelper
Did you mean
ar^5 : ar = 256 : 1 ?
if so, then
ar^5/(ar) = 256
r^4 = 256
r = ± 4
if r = 4, then ar^2 = 32
16a = 32
a = 2
if r = -4 , then
16a 32
a = 2
term(5) = ar^4 = 2(4)^4 = 512
the 2 sequences are either:
2, 8, 32, 128, 512, 2048, ....
or
2, -8, 32, -128, 512, -2048, ...
for either one term(1) = 2, and term(5) = 512
and for either one, the ratio of
term(6) : term(2) = 2048/8 or -2048/-8 = 256 in each case
ar^5 : ar = 256 : 1 ?
if so, then
ar^5/(ar) = 256
r^4 = 256
r = ± 4
if r = 4, then ar^2 = 32
16a = 32
a = 2
if r = -4 , then
16a 32
a = 2
term(5) = ar^4 = 2(4)^4 = 512
the 2 sequences are either:
2, 8, 32, 128, 512, 2048, ....
or
2, -8, 32, -128, 512, -2048, ...
for either one term(1) = 2, and term(5) = 512
and for either one, the ratio of
term(6) : term(2) = 2048/8 or -2048/-8 = 256 in each case
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