Question

4 stone of mass 5g is projected with a rubber catapult is stretched through a distance of 7cm by an average force of 7.0N calculate the instantaneous velocity of the stone when released

Answer 1

1/2 Fx = 1/2 mv^2
v^2 = Fx/m = 7 * 0.07 / 0.005 = 98
v = 9.9 m/s