Question
a stone projected horizontally from the top of a tower with a speed of 4m/s lands on the level ground at a horizontal distance 25m from the foot of the tower. calculate the height[g=10m/s2].
is it u squared divided by 2g
is it u squared divided by 2g
Answers
Horizontal problem:
u = 4 forever
d = 25
so
t = d/u = 25/4 seconds in air
vertical problem:
h = (1/2)g t^2
h = (1/2)g (d/u)^2
= (1/2)(10)(625/16)
u = 4 forever
d = 25
so
t = d/u = 25/4 seconds in air
vertical problem:
h = (1/2)g t^2
h = (1/2)g (d/u)^2
= (1/2)(10)(625/16)
Dx = Xo*Tf = 25 m.
4m/s * Tf = 25.
Tf = 6.25 s. = Fall time.
h = 0.5g*Tf^2.
4m/s * Tf = 25.
Tf = 6.25 s. = Fall time.
h = 0.5g*Tf^2.
3125/16
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