Asked by Lori
If 26.5 mL of 0.222 M HCl reacts with excess Mg, how many mL of hydrogen gas are produced at STP?
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Group of answer choices
65.9 mL
26.5 mL
132 mL
22 400 mL
165 mL
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Group of answer choices
65.9 mL
26.5 mL
132 mL
22 400 mL
165 mL
Answers
Answered by
DrBob222
millimols HCl used = mL x M = 26.5 mL x 0.222 M = approximately 5.88
Convert to millimoles H2 produced using the coefficients in the balanced equation this way. 5.88 millimiles HCl x (1 mole H2 gas/2 moles HCl) = 5.88 x 1/2 = 2.94 millimoles or 0.00294 moles H2 gas @ STP.
1 mol H2 will produce 22,400 mL so 0.00294 will produce ? mL H2 gas?
Post your work if you get stuck.
Convert to millimoles H2 produced using the coefficients in the balanced equation this way. 5.88 millimiles HCl x (1 mole H2 gas/2 moles HCl) = 5.88 x 1/2 = 2.94 millimoles or 0.00294 moles H2 gas @ STP.
1 mol H2 will produce 22,400 mL so 0.00294 will produce ? mL H2 gas?
Post your work if you get stuck.
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