Asked by Anonymous
A rectangular box has a square base and a height that is one more than 3 times the length of a side of the base. If the sides of the base are each increased by 2 inches and the height is increased by 3 inches the volume of the box increases by 531 cubic inches. What are the dimensions of the original box?
Answers
Answered by
oobleck
as before, you just need to solve
(x+2)^2 * (3x+1 + 3) = x^2(3x+1) + 531
solve for x, then finish it off
(x+2)^2 * (3x+1 + 3) = x^2(3x+1) + 531
solve for x, then finish it off
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