Asked by DAVID

P,Q & R ARE 3 VILLAGES SUCH THAT THE BEARING OF Q & R FROM P ARE 325 DEGREES & 055 DEGREES RESPECTIVELY.THE DISTANCE OF Q & R FROM P ARE 5KM & 9KM RESPECTIVELY CALCULATE CORRECT TO NEAREST DEGREE
a)the bearing of Q FROM P
b) the bearing of P from Q
c)DISTANCE OF R FROM Q
Answered by DAVID
PLS ANY RESPONSE
Answered by DS
1. Please stop using all-caps. On the internet, that’s interpreted as shouting. It’s not polite.

2. Please have patience. No tutors here are online 24/7.
Answered by DAVID
alright
Answered by mathhelper
This one is very similar to the one you posted previously.
I gave you a detailed solution, but you apparently did not understand, even
after I clarified it more.

e.g. in the previous problem one of the bearings was 300°. I claimed that
the remaining angle was 60°, and you did not understand it.
Don't know what else to say.
Answered by DAVID
I understood it but it was not so clear,well i understand it fully now.thank you
Answered by DAVID
do i use the same approach you used for the other question or is there another approach
Answered by oobleck
there's always another approach.
complex numbers, vectors, polar coordinates, geometry, algebra, etc.
Answered by DAVID
thank you but i don't know the approach to use
Answered by Anonymous
DRAW IT
Q is 35 deg w of n
R is 35 deg e of n
so angle QPR = 70 deg
setup for law of cosines
Answered by Anonymous
QR^2 = 5^2 + 9^2 - 2*5*9 cos 70 = 25 +81 - 30.8 = 75.2
so
QR = 8.67
Use the law of sines for the rest
I think you want the bearing of R not P from Q and you have a typo
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