Question

A car moves with uniform velocity of 12m/s for 6 sec. After this it accelerate at 2.0m/s² for 4 sec. It then travel for 2 more sec with uniform velocity . finally car decelerate to stop in 15 sec calculate. (a) the distance travelled in five seconds. (b) avarage velocity for the journey, assuming journey was in straight line.
(a) 12m/s * 5s = 60m
(b) total time: 6+4+2+15 = 27s
total distance: (12*6) + (12*4 + 1/2 * 2 * 4^2) + (20*2) + (20*15 - 1/2 * 4/3 * 15^2) = 326m

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