Component of force acting down the incline
F1 = mg sin(θ)
Normal component of weight (affects friction)
N = mg cos(θ)
Frictional force
Fr = μkN
Force exerted by engine to overcome gravity and friction
F= Fr + F1
car moves at a constant velocity up an inclined plane making an angle of 28degrees with the horizontal. The coefficient of friction is 0.387. The force exerted by the engine on the car is 588N.
Calculate the Following
A.weight of the car
B.frictional force acting on the car
1 answer