Asked by Ihuoma
A uniform metre tube of length 5m and mass 9kg is suspended horizontally by two vertical wires attached at 50cm and 150cm respectively from the ends of the tube. Calculate the tension in each wire
Answers
Answered by
Anonymous
force up at 50 = T1
weight down at 250 of 9 * 9.81= 88.3 N
force up at 350 = T2
total up = total down
T1 +T1 = 88.33
take moments about zero
50 T1 + 350 T2 = 250 * 88.3
weight down at 250 of 9 * 9.81= 88.3 N
force up at 350 = T2
total up = total down
T1 +T1 = 88.33
take moments about zero
50 T1 + 350 T2 = 250 * 88.3
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