Question

A body of mass 58g is suspended at 20cm mark of a uniform rule the meter rule is adjusted on a pivot until it settles horizontally at the40cm mark determine the mass of the meter rule

Answer 1

the 58 g is (40 - 20) or 20 cm from the pivot
the ruler mass m is (50 - 40) or 10 cm from the pivot
so
58 * 20 = m * 10
m = 116 grams

Answer 2

thanks allot

Answer 3

The 58g is (40-20)or 20cm from the pivot the ruler mass is (50-40)or 10cm from the pivot so 50*20=m*10 m=116 grams