Question

A body of mass 20g is suspended from the end of a spiral spring whose force constant is 0.5N/m. The body is set into a simple harmonic motion with amplitude 0.2m. Calculate the period of the motion?
bobpursley
period = 2PI sqrt (m/k) m is in kg, k in N/m
3.9 sec

Related Questions

The equation of the motion of a body suspended by a spring is T=2π√m/k, where T is the time period,... A body of mass 500g suspended from the end of a spiral spring which obeys Hooks law, produced an ext... A body of mass 500g suspended from the end of a spiral spring which obeys Hooke's law, produced an e... A body of mass 200g is suspended from the end of a spiral spring whose force constant is 0.8N/m. The...