Question
An object, suspended from a vertical spring, oscillates up and down at 3.76 Hz. How much would this object stretch the spring, if it were hanging at rest?
Answers
2 pi f= sqrt (k/m) = 2 pi * 3.76
so k/m = 558
m g = k X
X = 9.81 /558 meters
so k/m = 558
m g = k X
X = 9.81 /558 meters
Related Questions
A 1.0 kg object is suspended from a vertical spring whose spring constant is 105 N/m. The object is...
By how much will a 1.52 kg object stretch a spring that is suspended vertically if the spring consta...
A .2kg object attached to a vertical spring causes it to stretch 5.0cm. Another .2kg object is added...
Consider a vertical spring with spring constant 28.43 N/m hanging from the ceiling. A small object w...