Asked by Luca
                Determine the area of region by 𝒚 = x^2 + 4x and the y - axis.
            
            
        Answers
                    Answered by
            oobleck
            
    There is no such region bounded by the y-axis, but there is a region bounded by the x-axis: The area of the small loop which dips below the axis.  Since the curve intersects the axis at (-4,0) and (0,0), you want the area below y=0 and above the parabola. That would just be
∫[-4,0] (0 - (x^2+4x)) dx
or, using the symmetry of the region about the line x = -2, and cleaning up the minus signs,
-2∫[-2,0] (x^2 + 4x) dx
    
∫[-4,0] (0 - (x^2+4x)) dx
or, using the symmetry of the region about the line x = -2, and cleaning up the minus signs,
-2∫[-2,0] (x^2 + 4x) dx
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