Asked by Sophie
Which has more area, the region in the first quadrant enclosed by the line x+y=1 and the circle x^2+y^2=1, or the region in the first quadrant enclosed by the line x+y=1 and the curve sqrt(x)+sqrt(y)=1? Justify your answer.
Answers
Answered by
Reiny
Nice Question!!!
The first one we can do without Calculus, it is simply the segment between the chord from (0,1) to (1,0), that is
pi/4 - 1/2 = (pi - 2)/4
the second equation is
√x + √y = 1
or
√y = 1-√x
y = (1-√x)^2 = 1 - 2√x + x for 0 <= x <= 1
the integral of 1 - 2√x + x is x - (4/3)x^(3/2) + (1/2)x^2
and the area enclosed by √x + √y = 1 , the x-axis, and the y-axis is (from 0 to 1)
(1 - 4/3 + 1/2) - 0
= 1/6
So the area between the curve √x + √y = 1 and the line x+y=1 is
1/2 - 1/6 = 1/3
then (pi-2)/4 = .2854
1/3 = .33333
So who is bigger?
The first one we can do without Calculus, it is simply the segment between the chord from (0,1) to (1,0), that is
pi/4 - 1/2 = (pi - 2)/4
the second equation is
√x + √y = 1
or
√y = 1-√x
y = (1-√x)^2 = 1 - 2√x + x for 0 <= x <= 1
the integral of 1 - 2√x + x is x - (4/3)x^(3/2) + (1/2)x^2
and the area enclosed by √x + √y = 1 , the x-axis, and the y-axis is (from 0 to 1)
(1 - 4/3 + 1/2) - 0
= 1/6
So the area between the curve √x + √y = 1 and the line x+y=1 is
1/2 - 1/6 = 1/3
then (pi-2)/4 = .2854
1/3 = .33333
So who is bigger?
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