Question

A Baseball player leads off the game and hits along home run. The ball leaves the bat at an angle of 30° with a velocity of 70 m/s

•Determine the horizontal velocity (Vx) of the ball.
•Determine the vertical velocity (Vy) of the ball
• Determine the time when the ball will reach the highest point
•Determine the maximum range of the ball
•Determine the maximum height of the ball
Vx = 70 m/s * cos(30º)

Vy = 70 m/s * sin(30º)

time to max height ... Tmax = Vy / g

max range = Vx * 2 Tmax

max height ... Hmax = Tmax * Vy / 2

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