Question
A baseball player leads off the game and hits a long home run. The ball leaves the bat
at an angle of 30.0o
from the horizontal with a velocity of 40.0 m/s. How far will it
travel in the air?
Working out please
at an angle of 30.0o
from the horizontal with a velocity of 40.0 m/s. How far will it
travel in the air?
Working out please
Answers
Vo = 40m/s[30o]
Xo = 40*cos30 = 34.64 m/s.
Yo = 40*sin30 = 20 m/s.
Y = Yo + g*Tr = 0
Tr = -20/-9.8 = 2.04 s. = Rise time.
Y^2 = Yo^2 + 2g*h = 0
h = -(Yo^2)/2g = -(20^2)/-19.6=20.4 m.
h = 0.5g*t^2 = 20.4
4.9t^2 = 20.4
t^2 = 4.16
t = 2.04 s. = Fall time(Tf).
Range = Xo * (Tr+Tf)=34.64m/s * 4.08s. =
141.3 m.
Xo = 40*cos30 = 34.64 m/s.
Yo = 40*sin30 = 20 m/s.
Y = Yo + g*Tr = 0
Tr = -20/-9.8 = 2.04 s. = Rise time.
Y^2 = Yo^2 + 2g*h = 0
h = -(Yo^2)/2g = -(20^2)/-19.6=20.4 m.
h = 0.5g*t^2 = 20.4
4.9t^2 = 20.4
t^2 = 4.16
t = 2.04 s. = Fall time(Tf).
Range = Xo * (Tr+Tf)=34.64m/s * 4.08s. =
141.3 m.
How
Kate I think Your response is a little late
Bruh my teacher really had the same question this page has that was made in 2015