Asked by Kaur
k is the greatest number that divides 2996, 4752 and 7825 leaving the remainder in each case equal
I didn't understand as the answer done before
I didn't understand as the answer done before
Answers
Answered by
mathhelper
I was the one who answered you in this question.
h ttps://www.jiskha.com/questions/1894237/k-is-the-greatest-number-that-divides-2996-4752-and-7825-leaving-the-remainder-in-each
(delete the space at the front of the URL)
Both oobleck and i stated that we don't understand your actual question.
I don't expect you to follow the steps of how I found that highest
common divisor which leaves the same remainder, but I gave it to you
k = 439, common remainder = 362
Don't know what else you want us to do.
h ttps://www.jiskha.com/questions/1894237/k-is-the-greatest-number-that-divides-2996-4752-and-7825-leaving-the-remainder-in-each
(delete the space at the front of the URL)
Both oobleck and i stated that we don't understand your actual question.
I don't expect you to follow the steps of how I found that highest
common divisor which leaves the same remainder, but I gave it to you
k = 439, common remainder = 362
Don't know what else you want us to do.
Answered by
oobleck
mathhelper's little BASIC program divided the numbers by 1,2,3... until a common remainder was found. You could just as easily iterate by subttracting 1,2,3... from the numbers, and then finding the GCF of the diminished numbers. When the GCF is greater than 1, then you have found your answer.
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