Asked by Mia
In an arithmetic progression the sum of the 1st and 5th term is 18. The 5th term is 6 times more the 3rd term find the sum of the first 12 terms
Answers
Answered by
oobleck
a + a+4d = 18
a+4d = 6(a+2d)
solve for a and d, and then you want
S12 = 12/2 (2a+11d)
a+4d = 6(a+2d)
solve for a and d, and then you want
S12 = 12/2 (2a+11d)
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