Asked by greatmam
An arithmetic progression has 2 as its first term. find its common difference if the sum of 33 terms is equal to six times the sum of 13 terms
Answers
Answered by
Reiny
Sum(33) = 6Sum(13)
(33/2)(2a + 32d) = 6(13/2)(2a + 12d)
but a = 2
33(4 + 32d) = 78(4 + 12d)
sove for d
(33/2)(2a + 32d) = 6(13/2)(2a + 12d)
but a = 2
33(4 + 32d) = 78(4 + 12d)
sove for d
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