Asked by Anonymous
Use integration by parts to find the given integral:
∫_9^1 (7t - 42)e^(7 - t)
= [-28(1 + e^8)] / e^2
Is my answer correct?
or... is it..
= -70e^(-2) + 14e^6
∫_9^1 (7t - 42)e^(7 - t)
= [-28(1 + e^8)] / e^2
Is my answer correct?
or... is it..
= -70e^(-2) + 14e^6
Answers
Answered by
drwls
Is your 9^1 a misprint? What is the purpose of the 1? Why is there no "dt" in your integral?
Both of your answers are incorrect, since they are constants. The indefinite integral would be a function of t, and the definite integral would have to have specified limits of integration. You did not mention any.
Both of your answers are incorrect, since they are constants. The indefinite integral would be a function of t, and the definite integral would have to have specified limits of integration. You did not mention any.
Answered by
Anonymous
it's 1^9 and I forgot to include dt... and I need to evaluate it when f(9) - f(1) and that's what my answer represents..
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