Asked by Kaur
A game has 6 certain number of blue, red or black tokens. If you draw a token at random, the odds of getting a blue token are 1:2 and and the odds against getting a red token are 5:1.
a) If there are 32 blue tokens in this game, how many chips are there altogether?
b) If a against token is drawn at random, what are the odds of getting a black token ?
a) If there are 32 blue tokens in this game, how many chips are there altogether?
b) If a against token is drawn at random, what are the odds of getting a black token ?
Answers
Answered by
oobleck
If there are 32,y,z blue, red, black tokens, respectively,
32/(y+z) = 1/2
(32+z)/y = 5/1
Now you should be able to answer the questions (if you can figure out what (b) actually means)
32/(y+z) = 1/2
(32+z)/y = 5/1
Now you should be able to answer the questions (if you can figure out what (b) actually means)
Answered by
Kaur
Sorry didnt get it and i got confused for both parts.
Answered by
oobleck
solve those equations and you find that there were
32 blue, 16 red, 48 black
you shouldn't have any trouble now with the questions ...
32 blue, 16 red, 48 black
you shouldn't have any trouble now with the questions ...