Asked by Kaur
                A game has 6 certain number of blue, red or black tokens. If you draw a token at random, the odds of getting a blue token are 1:2 and and the odds against getting a red token are 5:1.
a) If there are 32 blue tokens in this game, how many chips are there altogether?
b) If a against token is drawn at random, what are the odds of getting a black token ?
            
        a) If there are 32 blue tokens in this game, how many chips are there altogether?
b) If a against token is drawn at random, what are the odds of getting a black token ?
Answers
                    Answered by
            oobleck
            
    If there are 32,y,z blue, red, black tokens, respectively,
32/(y+z) = 1/2
(32+z)/y = 5/1
Now you should be able to answer the questions (if you can figure out what (b) actually means)
    
32/(y+z) = 1/2
(32+z)/y = 5/1
Now you should be able to answer the questions (if you can figure out what (b) actually means)
                    Answered by
            Kaur
            
    Sorry didnt get it and i got confused for both parts.
    
                    Answered by
            oobleck
            
    solve those equations and you find that there were
32 blue, 16 red, 48 black
you shouldn't have any trouble now with the questions ...
    
32 blue, 16 red, 48 black
you shouldn't have any trouble now with the questions ...
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