Asked by Anonymous
                Andrew’s fruit shop had a total of 295 apples and pears. He sold 1/3 of the pears and bought another 50 apples. in the end, there was an equal number of apples and pears in the shop. How many more pears than apples were there in the shop at first.
            
            
        Answers
                    Answered by
            mathhelper
            
    at the start:
number of apples --- x
number of pears ---- 295-x
after transaction he has:
number of apples = 2x/3
number of pears = 295-x + 50 = 345 - x
they are the same, so ...
2x/3 = 345 - x
5x/3 = 345
x = 207
so at the start he had 207 apples, and 88 pears.
State your conclusion
    
number of apples --- x
number of pears ---- 295-x
after transaction he has:
number of apples = 2x/3
number of pears = 295-x + 50 = 345 - x
they are the same, so ...
2x/3 = 345 - x
5x/3 = 345
x = 207
so at the start he had 207 apples, and 88 pears.
State your conclusion
                    Answered by
            Anonymous 
            
    Incorrect answer. Respond back
    
                    Answered by
            Anonymous 
            
    It’s correct
    
                    Answered by
            mathhelper
            
    Actually I read it as:
He sold 1/3 of the apples and bought another 50 pears, so I had
the fruits backwards.
I think it would be a great learning experience if you corrected my
post. Let me know what the correct answer is that you got.
    
He sold 1/3 of the apples and bought another 50 pears, so I had
the fruits backwards.
I think it would be a great learning experience if you corrected my
post. Let me know what the correct answer is that you got.
                    Answered by
            Anonymous 
            
    It was 119 but your corrct
    
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