Asked by Kaur
                Find the rationalising factor of 
5^(1/3) + 5^(-1/3)
            
        5^(1/3) + 5^(-1/3)
Answers
                    Answered by
            mathhelper
            
    5^(1/3) + 5^(-1/3)
= 5^(1/3) + 1 / 5^(1/3) * 5(2/3)/5^(2/3)
= 5(1/3) + 5^(2/3) / 5
hope this is what you meant, there is no longer any irrational
number in the denominator.
    
= 5^(1/3) + 1 / 5^(1/3) * 5(2/3)/5^(2/3)
= 5(1/3) + 5^(2/3) / 5
hope this is what you meant, there is no longer any irrational
number in the denominator.
                    Answered by
            oobleck
            
    note that you can use the difference of cubes formula
x+y = (∛x + ∛y)(∛x^2 - ∛xy + ∛y^2)
so plug in x = 5 and y = 1/5
    
x+y = (∛x + ∛y)(∛x^2 - ∛xy + ∛y^2)
so plug in x = 5 and y = 1/5
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