Asked by Kaur
A rock is thrown in a pond, and creates circular ripples whose radius increases at a rate of 0.2 meter per second. What will be the value of dA/dt where A is the area (in square meter) of the circle after 5 seconds?
Answers
Answered by
mathhelper
A = πr^2
dA/dt = 2πr dr/dt
= ....
You are given dr/dt and
you know that after 5 seconds the radius will be 5s * .2m/s = 1 m
so just sub it in.
dA/dt = 2πr dr/dt
= ....
You are given dr/dt and
you know that after 5 seconds the radius will be 5s * .2m/s = 1 m
so just sub it in.
Answered by
Kaur
@mathhelper
I got 0.4pi m^2/sec
I got 0.4pi m^2/sec
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