Asked by mclovin

what are the value(s) in the interval, theta(- pi <= theta <= pi), satisfy the equation 6sin theta - 2 = sin theta? approximate your answer(s). please help!!
Answered by mathhelper
6sin θ - 2 = sin θ
5sinθ = 2
sinθ = 2/5
θ = appr .4115 radians,
or
θ = π - .4115 = appr 2.73

( make sure your calculator is set to radians (RAD on your DRG button)
to find sin^-1 (.4) )
Answered by mclovin
mathhelper Thank you so much!! :)
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