Asked by Harry
Find the points of discontinuity and any holes.
y=x^2-1/(x^2+3x+2)
please and thank you
y =(x^2-1)/((x+1)(x+2))
=(x-1)/(x+2)
we cancelled the (x+1)/(x+1) which is 0/0 for x=-1
so in our simplified expression when x=-1 y = -2
There is a "hole" at (-1,-2)
in the final expression the denominator cannot be zero, it is zero when x=-2
so the function is discontinuous at x=-2
so what are the points of discontinuity?
i thought that -1 and -2 were the pts of discontinuity
doesn't y=x^2-1/(x^2+3x+2)
=(x+1)(x-1)/(x-3)(x+1)
=x-1/x-3
since you factor it?
y=x^2-1/(x^2+3x+2)
please and thank you
y =(x^2-1)/((x+1)(x+2))
=(x-1)/(x+2)
we cancelled the (x+1)/(x+1) which is 0/0 for x=-1
so in our simplified expression when x=-1 y = -2
There is a "hole" at (-1,-2)
in the final expression the denominator cannot be zero, it is zero when x=-2
so the function is discontinuous at x=-2
so what are the points of discontinuity?
i thought that -1 and -2 were the pts of discontinuity
doesn't y=x^2-1/(x^2+3x+2)
=(x+1)(x-1)/(x-3)(x+1)
=x-1/x-3
since you factor it?
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.